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QJEEM22Ph3842: JEE Main 2022 Physics - Class 11 JEEM22Ph3842 Solution: A ball of mass 0.5 kg is dropped from the height of 10 m. The…

A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ________ m. [Use g = 10 m/s2]

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JEE Main 2022 (Online) 26th June Morning Shift Physics - Motion in a Straight Line Question 52 English Explanation

Let at h height its velocity becomes 10 m/s (as given in question)

⇒v2−u2=2(−10)×(−h)\Rightarrow {v^2} - {u^2} = 2( - 10) \times ( - h)

⇒v2=20 h\Rightarrow {v^2} = 20\,h

⇒100=20 h\Rightarrow 100 = 20\,h

⇒h=5 m\Rightarrow h = 5\,m

h′=10−5=5 mh' = 10 - 5 = 5\,m

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