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QJEEM22Ph3039: JEE Main 2022 Physics - Class 11 JEEM22Ph3039 Solution: A set of 20 tuning forks is arranged in a series of increasing…

A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is _________ Hz.

Step-by-Step Verified Solution

Given v20=2v1{v_{20}} = 2{v_1}

Also v20=4×19+v1{v_{20}} = 4 \times 19 + {v_1}

So v20=152 Hz{v_{20}} = 152\,Hz

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