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QJEEM22Ph286a: JEE Main 2022 Physics - Class 11 JEEM22Ph286a Solution: At a certain temperature, the degrees of freedom per molecule…

At a certain temperature, the degrees of freedom per molecule for gas is 8. The gas performs 150 J of work when it expands under constant pressure. The amount of heat absorbed by the gas will be _________ J.

Step-by-Step Verified Solution

f=8f = 8

W=P dV=150W = P\,dV = 150

Q=W+ΔUQ = W + \Delta U

=P dV+f2 PdV= P\,dV + {f \over 2}\,PdV

Q=5×150=750 JQ = 5 \times 150 = 750\,J

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