Verified Solution • 2025–26 Session moderate

QJEEM22Ph281a: JEE Main 2022 Physics - Class 12 JEEM22Ph281a Solution: The magnetic moment of an electron (e) revolving in an orbit…

The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by :

Multiple Choice Options

  • A μ⃗L=eL→2 m\vec{\mu}_{\mathrm{L}}=\frac{\overrightarrow{\mathrm{eL}}}{2 \mathrm{~m}}
  • B μ⃗L=−eL→2 m\vec{\mu}_{\mathrm{L}}=-\frac{\overrightarrow{\mathrm{eL}}}{2 \mathrm{~m}}
  • C μ⃗l=−eL→ m\vec{\mu}_{l}=-\frac{\overrightarrow{e L}}{\mathrm{~m}}
  • D μ⃗l=2eL→m\vec{\mu}_{l}=\frac{2 \overrightarrow{\mathrm{eL}}}{\mathrm{m}}

Step-by-Step Verified Solution

∵\because μ→=qL→2m\overrightarrow \mu = {{q\overrightarrow L } \over {2m}}

⇒μ→=−eL→2m\Rightarrow \overrightarrow \mu = {{ - e\overrightarrow L } \over {2m}}

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