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QJEEM22Ph273c: JEE Main 2022 Physics - Class 12 JEEM22Ph273c Solution: If the potential barrier across a p-n junction is . Then the…

If the potential barrier across a p-n junction is 0.6 V0.6 \mathrm{~V} . Then the electric field intensity, in the depletion region having the width of 6×10−6 m6 \times 10^{-6} \mathrm{~m} , will be __________ ×105 N/C\times 10^{5} \mathrm{~N} / \mathrm{C} .

Step-by-Step Verified Solution

E=Vd=0.66×10−6=1×105E = {V \over d} = {{0.6} \over {6 \times {{10}^{ - 6}}}} = 1 \times {10^5}

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