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QJEEM22Ph2659: JEE Main 2022 Physics - Class 12 JEEM22Ph2659 Solution: As shown in the figure an inductor of inductance 200 mH is…

As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is $\frac{\sqrt{a}}{π}$ A. The value of $a$ is ___________.

JEE Main 2022 (Online) 24th June Morning Shift Physics - Alternating Current Question 73 English

Step-by-Step Verified Solution

$I_{r m s} = \frac{V_{r m s}}{z}$

$z = X_{2} = ω_{2}$

$= 2 π \times 50 \times \frac{200}{1000}$

$= 20 π$

$∴$ $I_{r m s} = \frac{220}{20 π} = \frac{11}{π}$

$∴$ $I_{p e a k} = \sqrt{2} \times \frac{11}{π}$

$= \frac{\sqrt{2 \times 121}}{π}$

$= \frac{\sqrt{242}}{π}$

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