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QJEEM22Ph20fe: JEE Main 2022 Physics - Class 11 JEEM22Ph20fe Solution: A disc of mass 1   kg and radius R is free to rotate about …

A disc of mass 1 kg and radius R is free to rotate about a horizontal axis passing through its centre and perpendicular to the plane of disc. A body of same mass as that of disc is fixed at the highest point of the disc. Now the system is released, when the body comes to the lowest position, its angular speed will be 4x3Rrads−1 where x= ____________. (g=10 ms−2)

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JEE Main 2022 (Online) 26th July Morning Shift Physics - Rotational Motion Question 64 English Explanation

Loss in P.E. = Gain in K.E.

2mgR=12[12mR2+mR2]w2

2mgR=12×32mR2w2

w2=8g3R

w=8g3R=4g2×3R

⇒x=g2=5

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