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QJEEM22Ph1f86: JEE Main 2022 Physics - Class 12 JEEM22Ph1f86 Solution: A sinusoidal wave y(t) = 40sin(10 × 10 6 π t) is amplitude…

A sinusoidal wave y(t) = 40sin(10 × 106 πt) is amplitude modulated by another sinusoidal wave x(t) = 20sin (1000 πt). The amplitude of minimum frequency component of modulated signal is :

Multiple Choice Options

  • A 0.5
  • B 0.25
  • C 20
  • D 10

Step-by-Step Verified Solution

Modulate signal s(t)≡[1+20sin⁡(1000πt)]sin⁡(107πt)

≡sin⁡(107πt)+10cos⁡(107πt−103πt)+10cos⁡(107πt+103πt)

⇒ Required amplitude = 10

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