Verified Solution • 2025–26 Session moderate

QJEEM22Ph176f: JEE Main 2022 Physics - Class 11 JEEM22Ph176f Solution: The Vernier constant of Vernier callipers is 0.1 mm and it has…

The Vernier constant of Vernier callipers is 0.1 mm and it has zero error of (−0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be _________ × 10−2 cm.

Step-by-Step Verified Solution

Since zero error is negative, we will add 0.05 cm.

⇒ Corrected reading = 1.7 cm + 5 × 0.1 mm + 0.05 cm

= 180 × 10−2 cm

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring