Verified Solution • 2025–26 Session moderate

QJEEM22Ph1661: JEE Main 2022 Physics - Class 11 JEEM22Ph1661 Solution: The torque of a force about the origin is . If the force acts…

The torque of a force 5i^+3j^−7k^5 \hat{i}+3 \hat{j}-7 \hat{k} about the origin is τ\tau . If the force acts on a particle whose position vector is 2i+2j+k2 i+2 j+k , then the value of τ\tau will be

Multiple Choice Options

  • A 11i^+19j^−4k^11 \hat{i}+19 \hat{j}-4 \hat{k}
  • B −11i^+9j^−16k^-11 \hat{i}+9 \hat{j}-16 \hat{k}
  • C −17i^+19j^−4k^-17 \hat{i}+19 \hat{j}-4 \hat{k}
  • D 17i^+9j^+16k^17 \hat{i}+9 \hat{j}+16 \hat{k}

Step-by-Step Verified Solution

τ⃗=∣i^amp;j^amp;k^2amp;2amp;15amp;3amp;−7∣\vec{\tau}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 2 & 2 & 1 \\ 5 & 3 & -7\end{array}\right|

amp;=i^(−14−3)+j^(5+14)+k^(6−10)amp;=−17i^+19j^−4k^\begin{aligned}&=\hat{i}(-14-3)+\hat{j}(5+14)+\hat{k}(6-10) \\\\&=-17 \hat{i}+19 \hat{j}-4 \hat{k}\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring