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QJEEM22Ph1573: JEE Main 2022 Physics - Class 11 JEEM22Ph1573 Solution: The displacement of simple harmonic oscillator after 3 seconds…

The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is :

Multiple Choice Options

  • A 6 s
  • B 8 s
  • C 12 s
  • D 36 s

Step-by-Step Verified Solution

Time taken by the harmonic oscillator to move from mean position to half of amplitude is T12{T \over {12}}

So, T12{T \over {12}} = 3

T = 36 sec.

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