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QJEEM22Ph12b5: JEE Main 2022 Physics - Class 11 JEEM22Ph12b5 Solution: An object of mass 5 kg is thrown vertically upwards from the…

An object of mass 5 kg is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of 10 N throughout the motion. The ratio of time of ascent to the time of descent will be equal to : [Use g = 10 ms −- 2].

Multiple Choice Options

  • A 1:01
  • B 2\sqrt 2 : 3\sqrt 3
  • C 3\sqrt 3 : 2\sqrt 2
  • D 2:03

Step-by-Step Verified Solution

Let time taken to ascent is t1 and that to descent is t2. Height will be same so

H=12×12t12=12×8t22H = {1 \over 2} \times 12t_1^2 = {1 \over 2}\times8t_2^2

⇒t1t1=23\Rightarrow {{{t_1}} \over {{t_1}}} = {{\sqrt 2 } \over {\sqrt 3 }}

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