Verified Solution • 2025–26 Session moderate

QJEEM22Ph0e6e: JEE Main 2022 Physics - Class 11 JEEM22Ph0e6e Solution: A bullet is shot vertically downwards with an initial velocity…

A bullet is shot vertically downwards with an initial velocity of 100 m/s100 \mathrm{~m} / \mathrm{s} from a certain height. Within 10 s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time t=20 s\mathrm{t}=20 \mathrm{~s} will be:

(Take g = 10 m/s2).

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/7b595be03abb8a53166cfd398e8929d4738fe736d26bc6c47cf3bd32e6d64beb.webp
  • B https://ik.imagekit.io/novatra/photos/c685698aa040ab1129b193965bd98e90fcca037628e74011ca40dc0db9be5353.webp
  • C https://ik.imagekit.io/novatra/photos/eee70c283e263df32ad9d16598e6bf452e59df6f15bab4bf38ac7d90c1c69436.webp
  • D https://ik.imagekit.io/novatra/photos/5a452497c03b893ba9d8f894279ae2f717667d7e8d61f30cffe3d09967087b9b.webp

Step-by-Step Verified Solution

∣v10∣=(100+10×10)|{v_{10}}| = (100 + 10 \times 10) m/s

v10=−200{v_{10}} = - 200 m/s and v0=−100{v_0} = - 100 m/s

from 10s to 20s velocity remains zero

⇒\Rightarrow from t = 0s to 10s velocity increases in magnitude linearly.

⇒\Rightarrow graph given in option A fits correctly.

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