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QJEEM22Ph0df0: JEE Main 2022 Physics - Class 11 JEEM22Ph0df0 Solution: When a particle executes Simple Hormonic Motion, the nature of…

When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be :

Multiple Choice Options

  • A Circular
  • B Elliptical
  • C Sinusoidal
  • D Straight line

Step-by-Step Verified Solution

Let x=Asin⁡ωtx = A\sin \omega t

⇒v=Aωcos⁡ωt\Rightarrow v = A\omega \cos \omega t

⇒v= ± ωA2−x2\Rightarrow v = \, \pm \,\omega \sqrt {{A^2} - {x^2}}

⇒v2ω2+x2=A2\Rightarrow {{{v^2}} \over {{\omega ^2}}} + {x^2} = {A^2}

⇒\Rightarrow Ellipse

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