Verified Solution • 2025–26 Session moderate

QJEEM22Ph09bc: JEE Main 2022 Physics - Class 12 JEEM22Ph09bc Solution: A circular coil of 1000 turns each with area 1m 2 is rotated…

A circular coil of 1000 turns each with area 1m2 is rotated about its vertical diameter at the rate of one revolution per second in a uniform horizontal magnetic field of 0.07T. The maximum voltage generation will be ___________ V.

Step-by-Step Verified Solution

Vmax⁡=NABω{V_{\max }} = NAB\omega

=1000×1×0.07×(2π×1)= 1000 \times 1 \times 0.07 \times (2\pi \times 1)

≃440\simeq 440 volts

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