Verified Solution • 2025–26 Session moderate

QJEEM22Ph069e: JEE Main 2022 Physics - Class 12 JEEM22Ph069e Solution: Two sources of equal emfs are connected in series. This…

Two sources of equal emfs are connected in series. This combination is connected to an external resistance R. The internal resistances of the two sources are r1r_{1} and r2r_{2} \left(r_{1}>r_{2}\right) . If the potential difference across the source of internal resistance r1r_{1} is zero, then the value of R will be :

Multiple Choice Options

  • A r1−r2r_{1}-r_{2}
  • B r1r2r1+r2\frac{r_{1} r_{2}}{r_{1}+r_{2}}
  • C r1+r22\frac{r_{1}+r_{2}}{2}
  • D r2−r1r_{2}-r_{1}

Step-by-Step Verified Solution

JEE Main 2022 (Online) 27th July Morning Shift Physics - Current Electricity Question 121 English Explanation

ΔV=0⇒2εr1+r2+Rr1=ε\Delta V = 0 \Rightarrow {{2\varepsilon } \over {{r_1} + {r_2} + R}}{r_1} = \varepsilon

⇒R=r1−r2\Rightarrow R = {r_1} - {r_2}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring