QJEEM22Ph0628: JEE Main 2022 Physics - Class 12 JEEM22Ph0628 Solution: Two lighter nuclei combine to form a comparatively heavier…

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below :

$${}_1^{2}X+{}_1^{2}X={}_2^{4}Y$$

The binding energies per nucleon for $$\frac{2}{1}X$$ and $${}_2^{4}Y$$ are $$1.1\mathrm{MeV}$$ and $$7.6\mathrm{MeV}$$ respectively. The energy released in this process is _______________ $$\mathrm{MeV}$$.