Verified Solution • 2025–26 Session moderate

QJEEM22Ph0514: JEE Main 2022 Physics - Class 11 JEEM22Ph0514 Solution: At time a particle starts travelling from a height in a plane…

At time t=0t=0 a particle starts travelling from a height 7z^ cm7 \hat{z} \mathrm{~cm} in a plane keeping z coordinate constant. At any instant of time it's position along the x^\hat{x} and y^\hat{y} directions are defined as 3t3 \mathrm{t} and 5t35 \mathrm{t}^{3} respectively. At t = 1s acceleration of the particle will be

Multiple Choice Options

  • A −30y^-30 \hat{y}
  • B 30y^30 \hat{y}
  • C 3x^+15y^3 \hat{x}+15 \hat{y}
  • D 3x^+15y^+7z^3 \hat{x}+15 \hat{y}+7 \hat{z}

Step-by-Step Verified Solution

x=3t⇒ax=0x = 3t \Rightarrow {a_x} = 0

y=5t3⇒ay=30ty = 5{t^3} \Rightarrow {a_y} = 30t

a→(t=1)=30y^\overrightarrow a (t = 1) = 30\widehat y

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