QJEEM22Ph0294: JEE Main 2022 Physics - Class 12 JEEM22Ph0294 Solution: A source of potential difference V is connected to the…

A source of potential difference $$V$$ is connected to the combination of two identical capacitors as shown in the figure. When key '$$K$$' is closed, the total energy stored across the combination is $$E_1$$. Now key '$$K$$' is opened and dielectric of dielectric constant 5 is introduced between the plates of the capacitors. The total energy stored across the combination is now $$E_2$$. The ratio $$E_1/E_2$$ will be :