Verified Solution • 2025–26 Session moderate

QJEEM22Ph01fb: JEE Main 2022 Physics - Class 11 JEEM22Ph01fb Solution: If force acts on a particle position vector then, the torque…

If force F→=3i^+4j^−2k^\overrightarrow F = 3\widehat i + 4\widehat j - 2\widehat k acts on a particle position vector 2i^+j^+2k^2\widehat i + \widehat j + 2\widehat k then, the torque about the origin will be :

Multiple Choice Options

  • A 3i^+4j^−2k^3\widehat i + 4\widehat j - 2\widehat k
  • B −10i^+10j^+5k^- 10\widehat i + 10\widehat j + 5\widehat k
  • C 10i^+5j^−10k^10\widehat i + 5\widehat j - 10\widehat k
  • D 10i^+j^−5k^10\widehat i + \widehat j - 5\widehat k

Step-by-Step Verified Solution

τ→=r→×F→\overrightarrow \tau = \overrightarrow r \times \overrightarrow F

=(2i^+j^+2k^)×(3i^+4j^−2k^)= (2\widehat i + \widehat j + 2\widehat k) \times (3\widehat i + 4\widehat j - 2\widehat k)

=−10i^+10j^+5k^= - 10\widehat i + 10\widehat j + 5\widehat k

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