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QJEEM22Mafe7b: JEE Main 2022 Mathematics - Class 12 JEEM22Mafe7b Solution: The domain of the function , where [t] is the greatest integer…

The domain of the function f(x)=sin⁡−1[2x2−3]+log⁡2(log⁡12(x2−5x+5))f(x)=\sin ^{-1}\left[2 x^{2}-3\right]+\log _{2}\left(\log _{\frac{1}{2}}\left(x^{2}-5 x+5\right)\right) , where [t] is the greatest integer function, is :

Multiple Choice Options

  • A (−52,5−52)\left(-\sqrt{\frac{5}{2}}, \frac{5-\sqrt{5}}{2}\right)
  • B (5−52,5+52)\left(\frac{5-\sqrt{5}}{2}, \frac{5+\sqrt{5}}{2}\right)
  • C (1,5−52)\left(1, \frac{5-\sqrt{5}}{2}\right)
  • D [1,5+52)\left[1, \frac{5+\sqrt{5}}{2}\right)

Step-by-Step Verified Solution

- 1 \le 2{x^2} - 3 < 2

or 2 \le 2{x^2} < 5

or 1 \le {x^2} < {5 \over 2}

x∈(−52,−1]∪[1,52)x \in \left( { - \sqrt {{5 \over 2}} , - 1} \right] \cup \left[ {1,\sqrt {{5 \over 2}} } \right)

{\log _{{1 \over 2}}}({x^2} - 5x + 5) > 0

0 < {x^2} - 5x + 5 < 1

{x^2} - 5x + 5 > 0 & {x^2} - 5x + 4 < 0

x∈(−∞,5−52)∪(5+52,∞)x \in \left( { - \infty ,{{5 - \sqrt 5 } \over 2}} \right) \cup \left( {{{5 + \sqrt 5 } \over 2},\infty } \right)

& x∈(−∞,1)∪(4,∞)x \in ( - \infty ,1) \cup (4,\infty )

Taking intersection

x∈(1,5−52)x \in \left( {1,{{5 - \sqrt 5 } \over 2}} \right)

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