QJEEM22Mafc4b: JEE Main 2022 Mathematics - Class 11 JEEM22Mafc4b Solution: The number of elements in the set {z = a + ib C : a, b Z and 1…

at line $y=-2$ , we have $(5,-2)(6,-2)(1,-2)(0,-2)$ $\Rightarrow 4$ points

at line $y=-1$ , we have $(4,-1)(5,-1)(6,-1)(2,-1)$ $(1,-1)(0,-1) \Rightarrow 6$ points

at line $y=0$ , we have $(0,0)(1,0)(2,0)(3,0)(4,0)$ $(5,0)(6,0) \Rightarrow 7$ points

at line $y=1$ , we have $(1,1),(2,1),(3,1),(4,1),(5,1)$ i.e. 5 points

symmetrically

at line $y=-5$ , we have 5 points

at line $y=-4$ , we have 7 points

at line $y=-3$ , we have 6 points

So Total integral points $=2(5+7+6)+4$

$=40$