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QJEEM22Maf7d9: JEE Main 2022 Mathematics - Class 11 JEEM22Maf7d9 Solution: Let the abscissae of the two points P and Q on a circle be the…

Let the abscissae of the two points P and Q on a circle be the roots of x2−4x−6=0 and the ordinates of P and Q be the roots of y2+2y−7=0. If PQ is a diameter of the circle x2+y2+2ax+2by+c=0, then the value of (a+b−c) is _____________.

Multiple Choice Options

  • A 12
  • B 13
  • C 14
  • D 16

Step-by-Step Verified Solution

Abscissae of PQ are roots of x2−4x−6=0

Ordinates of PQ are roots of y2+2y−7=0

and PQ is diameter

⇒ Equation of circle is

x2+y2−4x+2y−13=0

But, given x2+y2+2ax+2by+c=0

By comparison a=−2,b=1,c=−13

⇒a+b−c=−2+1+13=12

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