Verified Solution • 2025–26 Session moderate

QJEEM22Maeec5: JEE Main 2022 Mathematics - Class 11 JEEM22Maeec5 Solution: Consider the following two propositions: If the proposition is…

Consider the following two propositions:

P1:∼(p→∼q)P1: \sim (p \to \sim q)

P2:(p∧∼q)∧((∼p)∨q)P2:(p \wedge \sim q) \wedge (( \sim p) \vee q)

If the proposition p→((∼p)∨q)p \to (( \sim p) \vee q) is evaluated as FALSE, then :

Multiple Choice Options

  • A P1 is TRUE and P2 is FALSE
  • B P1 is FALSE and P2 is TRUE
  • C Both P1 and P2 are FALSE
  • D Both P1 and P2 are TRUE

Step-by-Step Verified Solution

Given p→(∼p∨q)p \rightarrow(\sim p \vee q) is false

⇒∼p∨q\Rightarrow \sim p \vee q is false and pp is true

Now p=p= True.

∼T∨q=F\sim T \vee q=F

F∨q=F⇒qF \vee q=F \Rightarrow q is false

P1:∼(T→∼F)≡∼(T→T)≡P 1: \sim(T \rightarrow \sim F) \equiv \sim(T \rightarrow T) \equiv False.

P2:(T∧∼F)∧(∼T∨F)amp;≡(T∧T)∧(F∨F)amp;≡T∧F≡ False \begin{aligned}P 2:(T \wedge \sim F) \wedge(\sim T \vee F) & \equiv(T \wedge T) \wedge(F \vee F) \\\\& \equiv T \wedge F \equiv \text { False }\end{aligned}

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