Verified Solution • 2025–26 Session moderate

QJEEM22Maede8: JEE Main 2022 Mathematics - Class 11 JEEM22Maede8 Solution: Let and . Then, B :

Let A={z∈C:1≤∣z−(1+i)∣≤2}A = \{ z \in C:1 \le |z - (1 + i)| \le 2\}

and B={z∈A:∣z−(1−i)∣=1}B = \{ z \in A:|z - (1 - i)| = 1\} . Then, B :

Multiple Choice Options

  • A is an empty set
  • B contains exactly two elements
  • C contains exactly three elements
  • D is an infinite set

Step-by-Step Verified Solution

Let, z=x+iyz = x + iy

Given, 1≤∣z−(1+i)∣≤21 \le \left| {z - (1 + i)} \right| \le 2

⇒1≤∣x+iy−1−i∣≤2\Rightarrow 1 \le \left| {x + iy - 1 - i} \right| \le 2

⇒1≤∣(x−1)+i(y−1)∣≤2\Rightarrow 1 \le \left| {(x - 1) + i(y - 1)} \right| \le 2

⇒1≤(x−1)2+(y−1)2≤2\Rightarrow 1 \le \sqrt {{{(x - 1)}^2} + {{(y - 1)}^2}} \le 2

It represent two concentric circle both have center at (1, 1) and radius 1 and 2.

JEE Main 2022 (Online) 24th June Morning Shift Mathematics - Complex Numbers Question 72 English Explanation 1

Also given,

∣z−(1−i)∣=1\left| {z - (1 - i)} \right| = 1

⇒∣x+iy−1+i∣=1\Rightarrow \left| {x + iy - 1 + i} \right| = 1

⇒∣(x−1)+i(y+1)∣=1\Rightarrow \left| {(x - 1) + i(y + 1)} \right| = 1

⇒(x−1)2+(y+1)2=1\Rightarrow \sqrt {{{(x - 1)}^2} + {{(y + 1)}^2}} = 1

This represent a circle with center at (1, −- 1) and radius = 1.

JEE Main 2022 (Online) 24th June Morning Shift Mathematics - Complex Numbers Question 72 English Explanation 2

In the common region infinite values of B possible.

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