QJEEM22Mae82f: JEE Main 2022 Mathematics - Class 12 JEEM22Mae82f Solution: Let be the sample space of all five digit numbers. It is the…

Among the 5 digit numbers,

First number divisible by 7 is 10003 and last is 99995.

$\Rightarrow$ Number of numbers divisible by 7.

$= {{99995 - 10003} \over 7} + 1$

$= 12857$

First number divisible by 35 is 10010 and last is 99995.

$\Rightarrow$ Number of numbers divisible by 35

$= {{99995 - 10010} \over {35}} + 1$

$= 2572$

Hence number of number divisible by 7 but not by 5

$= 12857 - 2572$

$= 10285$

$9P. = {{10285} \over {90000}} \times 9$

$= 1.0285$