Verified Solution • 2025–26 Session moderate

QJEEM22Mab4dc: JEE Main 2022 Mathematics - Class 11 JEEM22Mab4dc Solution: Let A 1 , A 2 , A 3 , ....... be an increasing geometric…

Let A1, A2, A3, ....... be an increasing geometric progression of positive real numbers. If A1A3A5A7 = 11296{1 \over {1296}} and A2 + A4 = 736{7 \over {36}} , then the value of A6 + A8 + A10 is equal to

Multiple Choice Options

  • A 33
  • B 37
  • C 43
  • D 47

Step-by-Step Verified Solution

A4r3. A4r. A4r . A4r3=11296{{{A_4}} \over {{r^3}}}.\,{{{A_4}} \over r}.\,{A_4}r\,.\,{A_4}{r^3} = {1 \over {1296}}

A4=16{A_4} = {1 \over 6}

A2=736−16=136{A_2} = {7 \over {36}} - {1 \over 6} = {1 \over {36}}

So A6+A8+A10=1+6+36=43{A_6} + {A_8} + {A_{10}} = 1 + 6 + 36 = 43

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring