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QJEEM22Maac4e: JEE Main 2022 Mathematics - Class 12 JEEM22Maac4e Solution: Let f : R R be a continuous function such that . If , then is…

Let f : R →\to R be a continuous function such that f(3x)−f(x)=xf(3x) - f(x) = x . If f(8)=7f(8) = 7 , then f(14)f(14) is equal to :

Multiple Choice Options

  • A 4
  • B 10
  • C 11
  • D 16

Step-by-Step Verified Solution

f(3x)−f(x)=xf(3x) - f(x) = x ...... (1)

x→x3x \to {x \over 3}

f(x)−f(x3)=x3f(x) - f\left( {{x \over 3}} \right) = {x \over 3} ....... (2)

Again x→x3x \to {x \over 3}

f(x3)−f(x9)=x32f\left( {{x \over 3}} \right) - f\left( {{x \over 9}} \right) = {x \over {{3^2}}} ...... (3)

Similarly

f(x3n−2)−f(x3n−1)=x3n−1 ..... (n)f\left( {{x \over {{3^{n - 2}}}}} \right) - f\left( {{x \over {{3^{n - 1}}}}} \right) = {x \over {{3^{n - 1}}}}\,.....\,(n)

Adding all these and applying n→∞n \to \infty

lim⁡n→∞(f(3x)−f(x3n−1))=x(1+13+132 + ....)\mathop {\lim }\limits_{n \to \infty } \left( {f(3x) - f\left( {{x \over {{3^{n - 1}}}}} \right)} \right) = x\left( {1 + {1 \over 3} + {1 \over {{3^2}}}\, + \,....} \right)

f(3x)−f(0)=3x2f(3x) - f(0) = {{3x} \over 2}

Putting x=83x = {8 \over 3}

f(8)−f(0)=4f(8) - f(0) = 4

⇒f(0)=3\Rightarrow f(0) = 3

Putting x=143x = {{14} \over 3}

f(14)−3=7⇒f(14)=10f(14) - 3 = 7 \Rightarrow f(14) = 10

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