QJEEM22Ma9ece: JEE Main 2022 Mathematics - Class 11 JEEM22Ma9ece Solution: Let 3, 6, 9, 12, ....... upto 78 terms and 5, 9, 13, 17, ...... …

1st AP :

3, 6, 9, 12, ....... upto 78 terms

t₇₈ = 3 + (78 $$-$$ 1)3

= 3 + 77 $$\times$$ 3

= 234

2nd AP :

5, 9, 13, 17, ...... upto 59 terms

t₅₉ = 5 + (59 $$-$$ 1)4

= 5 + 58 $$\times$$ 4

= 237

Common term's AP :

First term = 9

Common difference of first AP = 3

And common difference of second AP = 4

$$\therefore$$ Common difference of common terms

AP = LCM (3, 4) = 12

$$\therefore$$ New AP = 9, 21, 33, .......

t_n = 9 + (n $$-$$ 1)12 $$\le$$ 234

$$\Rightarrow n\le \frac{237}{12}$$

$$\Rightarrow n=19$$

$$\therefore$$ $$S_{19}=\frac{19}{2}\left[2.9+(19-1)12\right]$$

$$=19(9+108)$$

$$=2223$$