Verified Solution • 2025–26 Session moderate

QJEEM22Ma7d27: JEE Main 2022 Mathematics - Class 12 JEEM22Ma7d27 Solution: A random variable X has the following probability distribution…

A random variable X has the following probability distribution :

X 0 1 2 3 4
P(X) k 2k 4k 6k 8k

The value of P(1 < X < 4 | X ≤ 2) is equal to :

Multiple Choice Options

  • A 47
  • B 23
  • C 37
  • D 45

Step-by-Step Verified Solution

∵ x is a random variable

∴ k+2k+4k+6k+8k=1

∴ k=121

Now, P(1<x<4|x≤2)=4k7k=47

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