Verified Solution • 2025–26 Session moderate

QJEEM22Ma7c5a: JEE Main 2022 Mathematics - Class 12 JEEM22Ma7c5a Solution: Let . Then the probability, that a randomly chosen number n…

Let S={1,2,3,…,2022}S=\{1,2,3, \ldots, 2022\} . Then the probability, that a randomly chosen number n from the set S such that HCF (n,2022)=1\mathrm{HCF}\,(\mathrm{n}, 2022)=1 , is :

Multiple Choice Options

  • A 1281011\frac{128}{1011}
  • B 1661011\frac{166}{1011}
  • C 127337\frac{127}{337}
  • D 112337\frac{112}{337}

Step-by-Step Verified Solution

S = {1, 2, 3, .......... 2022}

HCF (n, 2022) = 1

⇒\Rightarrow n and 2022 have no common factor

Total elements = 2022

2022 = 2 ×\times 3 ×\times 337

M : numbers divisible by 2.

{2, 4, 6, ........, 2022}     \,\,\,\, n(M) = 1011

N : numbers divisible by 3.

{3, 6, 9, ........, 2022}     \,\,\,\, n(N) = 674

L : numbers divisible by 6.

{6, 12, 18, ........, 2022}     \,\,\,\, n(L) = 337

n(M ∪\cup N) = n(M) + n(N) −- n(L)

= 1011 + 674 −- 337

= 1348

0 = Number divisible by 337 but not in M ∪\cup N

{337, 1685}

Number divisible by 2, 3 or 337

= 1348 + 2 = 1350

Required probability =2022−13502022= {{2022 - 1350} \over {2022}}

=6722022= {{672} \over {2022}}

=112337= {{112} \over {337}}

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