QJEEM22Ma5be5: JEE Main 2022 Mathematics - Class 11 JEEM22Ma5be5 Solution: The sum of all the elements of the set is __________.

The numbers upto 24 which gives g.c.d. with 24 equals to 1 are 1, 5, 7, 11, 13, 17, 19 and 23.

Sum of these numbers = 96

There are four such blocks and a number 97 is there upto 100.

$\therefore$ Complete sum

= 96 + (24 $\times$ 8 + 96) + (48 $\times$ 8 + 96) + (72 $\times$ 8 + 96) + 97

= 1633