Verified Solution • 2025–26 Session moderate

QJEEM22Ma5401: JEE Main 2022 Physics - Class 11 JEEM22Ma5401 Solution: Let S be the set of all a for which the angle between the…

Let S be the set of all a ∈R\in R for which the angle between the vectors u⃗=a(log⁡eb)i^−6j^+3k^\vec{u}=a\left(\log _{e} b\right) \hat{i}-6 \hat{j}+3 \hat{k} and v⃗=(log⁡eb)i^+2j^+2a(log⁡eb)k^\vec{v}=\left(\log _{e} b\right) \hat{i}+2 \hat{j}+2 a\left(\log _{e} b\right) \hat{k} , (b>1) is acute. Then S is equal to :

Multiple Choice Options

  • A (−∞,−43)\left(-\infty,-\frac{4}{3}\right)
  • B Φ\Phi
  • C (−43,0)\left(-\frac{4}{3}, 0\right)
  • D (127,∞)\left(\frac{12}{7}, \infty\right)

Step-by-Step Verified Solution

u→=a(log⁡eb)i^−6j^+3k^\overrightarrow u = a({\log _e}b)\widehat i - 6\widehat j + 3\widehat k

v→=(log⁡eb)i^+2j^+2a(log⁡eb)k^\overrightarrow v = ({\log _e}b)\widehat i + 2\widehat j + 2a({\log _e}b)\widehat k

For acute angle \overrightarrow u \,.\,\overrightarrow v > 0

\Rightarrow a{({\log _e}b)^2} - 12 + 6a({\log _e}b) > 0

∵\because b > 1

Let {\log _e}b = t \Rightarrow t > 0 as b > 1

a{t^2} + 6at - 12 > 0\,\,\,\,\,\,\,\forall t > 0

⇒a∈ϕ\Rightarrow a \in \phi

Related Learning Resources & Exam Preparation