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QJEEM22Ma4370: JEE Main 2022 Mathematics - Class 12 JEEM22Ma4370 Solution: The odd natural number a, such that the area of the region…

The odd natural number a, such that the area of the region bounded by y = 1, y = 3, x = 0, x = ya is 3643{{364} \over 3} , is equal to :

Multiple Choice Options

  • A 3
  • B 5
  • C 7
  • D 9

Step-by-Step Verified Solution

a\mathrm{a} is a odd natural number and

∣∫13yady∣=3643\left| {\int\limits_1^3 {{y^a}dy} } \right| = {{364} \over 3}

⇒∣1a+1(ya+1)13∣=3643\Rightarrow \left| {{1 \over {a + 1}}\left( {{y^{a + 1}}} \right)_1^3} \right| = {{364} \over 3}

⇒3a+1−1a+1= ± 3643\Rightarrow {{{3^{a + 1}} - 1} \over {a + 1}} = \, \pm \,{{364} \over 3}

Solving with (−)( - ) sign,

3a+1−1a+1=3643⇒(a=5){{{3^{a + 1}} - 1} \over {a + 1}} = {{364} \over 3} \Rightarrow (a = 5)

Solving with (+)( + ) sign,

3a+1−1a+1=−3643{{{3^{a + 1}} - 1} \over {a + 1}} = {{ - 364} \over 3} , No a exist

∴\therefore (a=5)(a = 5)

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