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QJEEM22Ma3f1d: JEE Main 2022 Mathematics - Class 12 JEEM22Ma3f1d Solution: The angle of elevation of the top of a tower from a point A due …

The angle of elevation of the top of a tower from a point A due north of it is $\alpha$ and from a point B at a distance of 9 units due west of A is $\cos ^{-1}\left(\frac{3}{\sqrt{13}}\right)$ . If the distance of the point B from the tower is 15 units, then $\cot \alpha$ is equal to :

Multiple Choice Options

A $\frac{6}{5}$
B $\frac{9}{5}$
C $\frac{4}{3}$
D $\frac{7}{3}$

Step-by-Step Verified Solution

JEE Main 2022 (Online) 29th July Morning Shift Mathematics - Height and Distance Question 4 English Explanation

$NA = \sqrt {{{15}^2} - {9^2}} = 12$

${h \over {15}} = \tan \theta = {2 \over 3}$

$h = 10$ units

$\cot \alpha = {{12} \over {10}} = {6 \over 5}$

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