Verified Solution • 2025–26 Session moderate

QJEEM22Ma38be: JEE Main 2022 Mathematics - Class 11 JEEM22Ma38be Solution: The number of bijective functions f : { 1 , 3 , 5 , 7 , … , 99…

The number of bijective functions f:{1,3,5,7,…,99}→{2,4,6,8,….100}, such that f(3)≥f(9)≥f(15)≥f(21)≥…..f(99), is ____________.

Multiple Choice Options

  • A 50P17
  • B 50P33
  • C 33!×17!
  • D 50!2

Step-by-Step Verified Solution

As function is one-one and onto, out of 50 elements of domain set 17 elements are following restriction f(3)>f(9)>f(15).......>f(99)

So number of ways =50C17.1.33!

=50P33

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