QJEEM22Ma2cc9: JEE Main 2022 Mathematics - Class 12 JEEM22Ma2cc9 Solution: Let S = {E 1 , E 2 , ........., E 8 } be a sample space of a…

Here $P({E_n}) = {n \over {36}}$ for n = 1, 2, 3, ......, 8

Here $P(A) = {{Any\,possible\,sum\,of\,(1,2,3,\,...,\,8)( = a\,say)} \over {36}}$

$\because$ ${a \over {36}} \ge {4 \over 5}$

$\therefore$ $a \ge 29$

If one of the number from {1, 2, ......, 8} is left then total $a \ge 29$ by 3 ways.

Similarly by leaving terms more 2 or 3 we get 16 more combinations.

$\therefore$ Total number of different set A possible is 16 + 3 = 19