QJEEM22Ma26ad: JEE Main 2022 Mathematics - Class 12 JEEM22Ma26ad Solution: The area bounded by the curves and is

Area $= 2\int\limits_0^{\sqrt 2 } {(1 - |{x^2} - 1|)dx}$

$2\left[ {\int\limits_0^1 {\left( {1 - (1 - {x^2})} \right)dx + \int\limits_1^{\sqrt 2 } {\left( {2 - {x^2}} \right)dx} } } \right]$

$= 2\left[ {\left. {\left[ {{{{x^3}} \over 3}} \right]_0^1 + \left[ {2x - {{{x^3}} \over 3}} \right]_1^{\sqrt 2 }} \right]} \right]$

$= 2\left( {{{4\sqrt 2 - 4} \over 3}} \right) = {8 \over 3}\left( {\sqrt 2 - 1} \right)$