Verified Solution • 2025–26 Session moderate

QJEEM22Ma1395: JEE Main 2022 Mathematics - Class 11 JEEM22Ma1395 Solution: Let and be two relations defined on by and Then,

Let R1R_{1} and R2R_{2} be two relations defined on R\mathbb{R} by

a R1 b⇔ab≥0a \,R_{1} \,b \Leftrightarrow a b \geq 0 and a R2 b⇔a≥ba \,R_{2} \,b \Leftrightarrow a \geq b

Then,

Multiple Choice Options

  • A R1R_{1} is an equivalence relation but not R2R_{2}
  • B R2R_{2} is an equivalence relation but not R1R_{1}
  • C both R1R_{1} and R2R_{2} are equivalence relations
  • D neither R1R_{1} nor R2R_{2} is an equivalence relation

Step-by-Step Verified Solution

a R1 b⇔ab≥0a\,{R_1}\,b \Leftrightarrow ab \ge 0

So, definitely (a,a)∈R1(a,a) \in {R_1} as a2≥0{a^2} \ge 0

If (a,b)∈R1⇒(b,a)∈R1(a,b) \in {R_1} \Rightarrow (b,a) \in {R_1}

But if (a,b)∈R1,(b,c)∈R1(a,b) \in {R_1},(b,c) \in {R_1}

⇒\Rightarrow Then (a,c)(a,c) may or may not belong to R1

{Consider a=−5,b=0,c=5a = - 5,b = 0,c = 5 so (a,b)(a,b) and (b,c)∈R1(b,c) \in {R_1} but ac < 0 }

So, R1 is not equivalence relation

a R2 b⇔a≥ba\,{R_2}\,b \Leftrightarrow a \ge b

(a,a)∈R2⇒(a,a) \in {R_2} \Rightarrow so reflexive relation

If (a,b)∈R2(a,b) \in {R_2} then (b,a)(b,a) may or may not belong to R2

⇒\Rightarrow So not symmetric

Hence it is not equivalence relation

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