Verified Solution • 2025–26 Session moderate

QJEEM22Ma07be: JEE Main 2022 Mathematics - Class 11 JEEM22Ma07be Solution: If z = x + i y satisfies

If z=x+iy satisfies |z|−2=0 and |z−i|−|z+5i|=0, then :

Multiple Choice Options

  • A x+2y−4=0
  • B x2+y−4=0
  • C x+2y+4=0
  • D x2−y+3=0

Step-by-Step Verified Solution

|z−i|=|z+5i|

So, z lies on ⊥r bisector of (0,1) and (0,−5)

i.e., line y=−2

as |z|=2

⇒z=−2i

x=0 and y=−2

so, x+2y+4=0

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