QJEEM22Ma048e: JEE Main 2022 Mathematics - Class 12 JEEM22Ma048e Solution: Let for every n N. Then the sum of all the elements of the set…

$\because$ ${a_n} = \int\limits_{ - 1}^n {\left( {1 + {x \over 2} + {{{x^2}} \over 3}\, + \,....\, + \,{{{x^{n - 1}}} \over n}} \right)dx}$

$= \left[ {x + {{{x^2}} \over {{2^2}}} + {{{x^3}} \over {{3^2}}}\, + \,......\, + \,{{{x^n}} \over {{n^2}}}} \right]_{ - 1}^n$

${a_n} = {{n + 1} \over {{1^2}}} + {{{n^2} - 1} \over {{2^2}}} + {{{n^3} + 1} \over {{3^2}}} + {{{n^4} - 1} \over {{4^2}}}\, + \,...\, + \,{{{n^n} + {{( - 1)}^{n + 1}}} \over {{n^2}}}$

Here, ${a_1} = 2,\,{a_2} = {{2 + 1} \over 1} + {{{2^2} - 1} \over 2} = 3 + {3 \over 2} = {9 \over 2}$

${a_3} = 4 + 2 + {{28} \over 9} = {{100} \over 9}$

{a_4} = 5 + {{15} \over 4} + {{65} \over 9} + {{255} \over {16}} > 31 .

$\therefore$ The required set is $\{ 2,3\}$ . $\because$ ${a_n} \in (2,30)$

$\therefore$ Sum of elements = 5.