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QJEEM22Chf969: JEE Main 2022 Chemistry - Class 12 JEEM22Chf969 Solution: Sum of oxidation state (magnitude) and coordination number of…

Sum of oxidation state (magnitude) and coordination number of cobalt in Na[Co(bpy)Cl4]\mathrm{Na}\left[\mathrm{Co}(\mathrm{bpy}) \mathrm{Cl}_{4}\right] is _________.

JEE Main 2022 (Online) 29th July Evening Shift Chemistry - Coordination Compounds Question 114 English

Step-by-Step Verified Solution

Na[Co(bpy)Cl4]\mathrm{Na}\left[\mathrm{Co}(\mathrm{bpy}) \mathrm{Cl}_{4}\right]

Oxidation state of cobalt =+3=+3

Coordination number of cobalt =6=6

[As bpy is bidentate]

So, sum =9=9

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