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QJEEM22Chf231: JEE Main 2022 Chemistry - Class 11 JEEM22Chf231 Solution: In bromination of Propyne, with Bromine, 1, 1, 2,…

In bromination of Propyne, with Bromine, 1, 1, 2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2-tetrabromopropane obtained from 1 g of Bromine in this reaction is ___________ ×\times 10 −- 1 g. (Nearest integer)

(Molar Mass : Bromine = 80 g/mol)

Step-by-Step Verified Solution

JEE Main 2022 (Online) 29th July Morning Shift Chemistry - Practical Organic Chemistry Question 30 English Explanation
2 moles Br2≡1\mathrm{Br}_{2} \equiv 1 mole 1,1,2,2-tetrabromopropane 1160\frac{1}{160} mole Br2\mathrm{Br}_{2}

≡12×1160\equiv \frac{1}{2} \times \frac{1}{160} mole 1,1,2,2-tetrabromopropane

But yield of reaction is only 27%27 \%

Moles of 1,1,2,2-tetrabromopropane

=12×1160×27100=\frac{1}{2} \times \frac{1}{160} \times \frac{27}{100}

Molar mass of 1,1,2,2-tetrabromopropane =360 g=360 \mathrm{~g} Mass of 1,1,2,2-tetrabromopropane

amp;=12×1160×27100×360 gamp;≈3×10−1 g\begin{aligned}&=\frac{1}{2} \times \frac{1}{160} \times \frac{27}{100} \times 360 \mathrm{~g} \\\\&\approx 3 \times 10^{-1} \mathrm{~g}\end{aligned}

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