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QJEEM22Ched9e: JEE Main 2022 Chemistry - Class 11 JEEM22Ched9e Solution: Lithium nitrate and sodium nitrate, when heated separately,…

Lithium nitrate and sodium nitrate, when heated separately, respectively, give :

Multiple Choice Options

  • A LiNO2\mathrm{LiNO}_{2} and NaNO2\mathrm{NaNO}_{2}
  • B Li2O\mathrm{Li}_{2} \mathrm{O} and Na2O\mathrm{Na}_{2} \mathrm{O}
  • C Li2O\mathrm{Li}_{2} \mathrm{O} and NaNO2\mathrm{NaNO}_{2}
  • D LiNO2\mathrm{LiNO}_{2} and Na2O\mathrm{Na}_{2} \mathrm{O}

Step-by-Step Verified Solution

Li2O,NaNO2\mathrm{Li}_{2} \mathrm{O}, \mathrm{NaNO}_{2}

As per NCERT lithium nitrate when heated gives lithium oxide, Li2O\mathrm{Li}_{2} \mathrm{O} . Whereas other alkali metal nitrates decompose to give the corresponding nitrite.

4LiNO3⟶2Li2O+4NO2+O24 \mathrm{LiNO}_{3} \longrightarrow 2 \mathrm{Li}_{2} \mathrm{O}+4 \mathrm{NO}_{2}+\mathrm{O}_{2}

2NaNO3⟶2NaNO2+O22 \mathrm{NaNO}_{3} \longrightarrow 2 \mathrm{NaNO}_{2}+\mathrm{O}_{2}

However, the decomposition product of NaNO3\mathrm{NaNO}_{3} is temperature dependent process as shown in the below reaction.

NaNO3⟶Δ500∘CNaNO2( s)+12O2( g)\mathrm{NaNO}_{3} \underset{500^{\circ} \mathrm{C}}{\stackrel{\Delta}{\longrightarrow}} \mathrm{NaNO}_{2}(\mathrm{~s})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})
                       Δ↓,800∘C\Delta \downarrow, 800^{\circ} \mathrm{C}
                       Na2O(s)+N2( g)+O2( g)\mathrm{Na}_{2} \mathrm{O}(\mathrm{s})+\mathrm{N}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})

As the temperature is not mentioned, we can go by the answer. (C)

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