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QJEEM22Cheac4: JEE Main 2022 Chemistry - Class 12 JEEM22Cheac4 Solution: Reaction of [Co(H 2 O) 6 ] 2+ with excess ammonia and in the…

Reaction of [Co(H2O)6]2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t2g-orbitals of the product is ___________.

Step-by-Step Verified Solution

[Co(H2O)6]+2⟶NH3O2[Co(NH3)6]+3+e−\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{+2} \underset{\mathrm{O}_{2}}{\stackrel{\mathrm{NH}_{3}}{\longrightarrow}}\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{+3}+e^{-}

Co+3⟶3 d6\mathrm{Co}^{+3} \longrightarrow 3 \mathrm{~d}^{6}

NH3\mathrm{NH}_{3} is a strong field ligand.

3 d6⟶t2 g6 eg∘3 \mathrm{~d}^{6} \longrightarrow \mathrm{t}_{2 \mathrm{~g}}^{6} ~\mathrm{eg}^{\circ}

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