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QJEEM22Che37d: JEE Main 2022 Chemistry - Class 11 JEEM22Che37d Solution: A gas (Molar mass = 280   g   mol − 1 ) was burnt in…

A gas (Molar mass = 280  g mol−1) was burnt in excess O2 in a constant volume calorimeter and during combustion the temperature of calorimeter increased from 298.0 K to 298.45 K. If the heat capacity of calorimeter is 2.5 kJ K−1 and enthalpy of combustion of gas is 9 kJ mol−1 then amount of gas burnt is _____________ g. (Nearest Integer)

Step-by-Step Verified Solution

ΔU=CΔT\Delta \mathrm{U}=\mathrm{C} \Delta \mathrm{T}

=2.5×103×0.45=1.125 kJ

Considering ΔH≃ΔU\Delta \mathrm{H} \simeq \Delta \mathrm{U}

ΔH=9 kJ/mol≃ΔU

∴\therefore Mass of gas burnt =1.1259×280=35 g=\frac{1.125}{9} \times 280=35 \mathrm{~g}

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