Verified Solution • 2025–26 Session moderate

QJEEM22Che23f: JEE Main 2022 Chemistry - Class 11 JEEM22Che23f Solution: Consider the following statements : (A) The principal quantum…

Consider the following statements :

(A) The principal quantum number 'n' is a positive integer with values of 'n' = 1, 2, 3, ...

(B) The azimuthal quantum number 'l' for a given 'n' (principal quantum number) can have values as 'l' = 0, 1, 2, ...... n

(C) Magnetic orbital quantum number 'ml' for a particular 'l' (azimuthal quantum number) has (2l + 1) values.

(D) ±\pm 1/2 are the two possible orientations of electron spin.

(E) For l = 5, there will be a total of 9 orbital

Which of the above statements are correct?

Multiple Choice Options

  • A (A), (B) and (C)
  • B (A), (C), (D) and (E)
  • C (A), (C) and (D)
  • D (A), (B), (C) and (D)

Step-by-Step Verified Solution

(A) Principle quantum number n is a positive integer and it's possible values are n = 1, 2, 3 ........

∴\therefore A is correct.

(B) Azimuthal quantum number 'l' for a given 'n' can have values as l = 0, 1, 2 ....... (n −- 1)

∴\therefore Statement B is wrong.

(C) Magnetic orbital quantum number ml for particular l has values from −- l to + 1 including zero means 2l + 1 values.

∴\therefore Statement C is correct.

(D) ±  12\pm \,\,{1 \over 2} are the two possible orientation of electron spin.

∴\therefore Statement D is correct.

(E) For l = 5, there will be a total of 11 orbitals.

ll = 0 ⇒\Rightarrow 5 subshell

ll = 1 ⇒\Rightarrow p subshell

ll = 2 ⇒\Rightarrow d subshell

ll = 3 ⇒\Rightarrow f subshell

ll = 4 ⇒\Rightarrow g subshell

ll = 5 ⇒\Rightarrow h subshell

We know,

Number of orbital in any subshell = 2 ll + 1.

∴\therefore For h subshell, number of orbitals = 2 ×\times 5 + 1 = 11

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