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QJEEM22Chd9e9: JEE Main 2022 Chemistry - Class 11 JEEM22Chd9e9 Solution: The correct decreasing order of energy for the orbitals having, …
The correct decreasing order of energy for the orbitals having, following set of quantum numbers :
(A) n = 3, l = 0, m = 0
(B) n = 4, l = 0, m = 0
(C) n = 3, l = 1, m = 0
(D) n = 3, l = 2, m = 1
is :
Multiple Choice Options
- A (D) > (B) > (C) > (A)
- B (B) > (D) > (C) > (A)
- C (C) > (B) > (D) > (A)
- D (B) > (C) > (D) > (A)
Step-by-Step Verified Solution
(A)
(B)
(C)
(D)
Higher valuc, higher the encrgy & if same value, then higher value, higher the energy.
Thus : \mathrm{D}>\mathrm{B}>\mathrm{C}>\mathrm{A} .
(B)
(C)
(D)
Higher valuc, higher the encrgy & if same value, then higher value, higher the energy.
Thus : \mathrm{D}>\mathrm{B}>\mathrm{C}>\mathrm{A} .