Verified Solution • 2025–26 Session moderate

QJEEM22Chd65f: JEE Main 2022 Chemistry - Class 12 JEEM22Chd65f Solution: The equation k = (6.5 10 12 s 1 )e 26000K/T is followed for the …

The equation

k = (6.5 ×\times 1012s −- 1)e −- 26000K/T

is followed for the decomposition of compound A. The activation energy for the reaction is ________ kJ mol −- 1. [nearest integer]

(Given : R = 8.314 J K −- 1 mol −- 1)

Step-by-Step Verified Solution

k=Ae−EaRTk=A e^{\frac{-E_{a}}{R T}}

EaRTamp;=26000TEaamp;=26000×8.314amp;=216164 Jamp;=216 kJ\begin{aligned}\frac{E_{a}}{R T} &=\frac{26000}{T} \\\\E_{a} &=26000 \times 8.314 \\\\&=216164 \mathrm{~J} \\\\&=216 \mathrm{~kJ}\end{aligned}

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