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QJEEM22Chd571: JEE Main 2022 Chemistry - Class 11 JEEM22Chd571 Solution: 2L of 0.2M H 2 SO 4 is reacted with 2L of 0.1M NaOH solution,…

2L of 0.2M H2SO4 is reacted with 2L of 0.1M NaOH solution, the molarity of the resulting product Na2SO4 in the solution is _________ millimolar. (Nearest integer)

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JEE Main 2022 (Online) 28th July Evening Shift Chemistry - Some Basic Concepts of Chemistry Question 80 English Explanation
Molarity of Na2SO4\mathrm{Na}_2 \mathrm{SO}_4 is 0.14=0.025 M\frac{0.1}{4}=0.025 \,\mathrm{M}

=25 mM=25 \,\mathrm{mM}

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